Base | Representation |
---|---|
bin | 10111000110010111… |
… | …00101011011101011 |
3 | 1012000021102100222202 |
4 | 23203023211123223 |
5 | 200344224241111 |
6 | 5410325010415 |
7 | 616214104523 |
oct | 134313453353 |
9 | 35007370882 |
10 | 12401399531 |
11 | 52942a3024 |
12 | 24a1253a0b |
13 | 1228376141 |
14 | 859068683 |
15 | 4c8b0db3b |
hex | 2e32e56eb |
12401399531 has 2 divisors, whose sum is σ = 12401399532. Its totient is φ = 12401399530.
The previous prime is 12401399501. The next prime is 12401399537. The reversal of 12401399531 is 13599310421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12401399531 - 210 = 12401398507 is a prime.
It is a super-2 number, since 2×124013995312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12401399537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200699765 + 6200699766.
It is an arithmetic number, because the mean of its divisors is an integer number (6200699766).
Almost surely, 212401399531 is an apocalyptic number.
12401399531 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401399531 is an equidigital number, since it uses as much as digits as its factorization.
12401399531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 38.
The spelling of 12401399531 in words is "twelve billion, four hundred one million, three hundred ninety-nine thousand, five hundred thirty-one".
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