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12401626415197 is a prime number
BaseRepresentation
bin1011010001110111101010…
…0010011000000001011101
31121220120202200000221000011
42310131322202120001131
53111142012330241242
642213121210003221
72416662602141545
oct264357242300135
947816680027004
1012401626415197
113a5155588aa98
121483627716511
136bc611c82086
1430c355b90325
151678dc4d4d17
hexb477a89805d

12401626415197 has 2 divisors, whose sum is σ = 12401626415198. Its totient is φ = 12401626415196.

The previous prime is 12401626415131. The next prime is 12401626415239. The reversal of 12401626415197 is 79151462610421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6415916757156 + 5985709658041 = 2532966^2 + 2446571^2 .

It is a cyclic number.

It is not a de Polignac number, because 12401626415197 - 211 = 12401626413149 is a prime.

It is a super-2 number, since 2×124016264151972 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12401626415197.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12401626419197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200813207598 + 6200813207599.

It is an arithmetic number, because the mean of its divisors is an integer number (6200813207599).

Almost surely, 212401626415197 is an apocalyptic number.

It is an amenable number.

12401626415197 is a deficient number, since it is larger than the sum of its proper divisors (1).

12401626415197 is an equidigital number, since it uses as much as digits as its factorization.

12401626415197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 49.

The spelling of 12401626415197 in words is "twelve trillion, four hundred one billion, six hundred twenty-six million, four hundred fifteen thousand, one hundred ninety-seven".