Base | Representation |
---|---|
bin | 10010000011000001110… |
… | …000101011000101000101 |
3 | 11101120011202121221120020 |
4 | 102003001300223011011 |
5 | 130304413020441201 |
6 | 2345423550525353 |
7 | 155413226324364 |
oct | 22030160530505 |
9 | 4346152557506 |
10 | 1240201343301 |
11 | 438a6a365358 |
12 | 180438b06859 |
13 | 8cc482a4acb |
14 | 440517477db |
15 | 223d91e4a36 |
hex | 120c1c2b145 |
1240201343301 has 4 divisors (see below), whose sum is σ = 1653601791072. Its totient is φ = 826800895532.
The previous prime is 1240201343267. The next prime is 1240201343341. The reversal of 1240201343301 is 1033431020421.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1240201343301 - 26 = 1240201343237 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1240201343341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206700223881 + ... + 206700223886.
It is an arithmetic number, because the mean of its divisors is an integer number (413400447768).
Almost surely, 21240201343301 is an apocalyptic number.
It is an amenable number.
1240201343301 is a deficient number, since it is larger than the sum of its proper divisors (413400447771).
1240201343301 is an equidigital number, since it uses as much as digits as its factorization.
1240201343301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 413400447770.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 1240201343301 its reverse (1033431020421), we get a palindrome (2273632363722).
The spelling of 1240201343301 in words is "one trillion, two hundred forty billion, two hundred one million, three hundred forty-three thousand, three hundred one".
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