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124020213 = 343961397
BaseRepresentation
bin1110110010001…
…10010111110101
322122100212202020
413121012113311
5223222121323
620150103353
73034103652
oct731062765
9278325666
10124020213
1164008249
123564ab59
131c903a55
1412684c29
15ad4bae3
hex76465f5

124020213 has 8 divisors (see below), whose sum is σ = 169206048. Its totient is φ = 80757264.

The previous prime is 124020179. The next prime is 124020271. The reversal of 124020213 is 312020421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 124020213 - 217 = 123889141 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 124020192 and 124020201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124021213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 480570 + ... + 480827.

It is an arithmetic number, because the mean of its divisors is an integer number (21150756).

Almost surely, 2124020213 is an apocalyptic number.

It is an amenable number.

124020213 is a deficient number, since it is larger than the sum of its proper divisors (45185835).

124020213 is an equidigital number, since it uses as much as digits as its factorization.

124020213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 961443.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 124020213 is about 11136.4362791694. The cubic root of 124020213 is about 498.6901891204.

Adding to 124020213 its reverse (312020421), we get a palindrome (436040634).

The spelling of 124020213 in words is "one hundred twenty-four million, twenty thousand, two hundred thirteen".

Divisors: 1 3 43 129 961397 2884191 41340071 124020213