Search a number
-
+
124020422151433 is a prime number
BaseRepresentation
bin11100001100101111000001…
…001101010000110100001001
3121021010020101110100112000121
4130030233001031100310021
5112223422311032321213
61115434110112303241
735060115450465343
oct3414570115206411
9537106343315017
10124020422151433
113657584710a485
1211aabba4541b21
1354280ca1c9082
14228a898784293
15e510c846888d
hex70cbc1350d09

124020422151433 has 2 divisors, whose sum is σ = 124020422151434. Its totient is φ = 124020422151432.

The previous prime is 124020422151397. The next prime is 124020422151443. The reversal of 124020422151433 is 334151224020421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97405688002624 + 26614734148809 = 9869432^2 + 5158947^2 .

It is a cyclic number.

It is not a de Polignac number, because 124020422151433 - 245 = 88836050062601 is a prime.

It is a super-2 number, since 2×1240204221514332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (124020422151443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62010211075716 + 62010211075717.

It is an arithmetic number, because the mean of its divisors is an integer number (62010211075717).

Almost surely, 2124020422151433 is an apocalyptic number.

It is an amenable number.

124020422151433 is a deficient number, since it is larger than the sum of its proper divisors (1).

124020422151433 is an equidigital number, since it uses as much as digits as its factorization.

124020422151433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 124020422151433 its reverse (334151224020421), we get a palindrome (458171646171854).

The spelling of 124020422151433 in words is "one hundred twenty-four trillion, twenty billion, four hundred twenty-two million, one hundred fifty-one thousand, four hundred thirty-three".