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12402175406471 is a prime number
BaseRepresentation
bin1011010001111001101101…
…0000100111000110000111
31121220122011221001120110022
42310132123100213012013
53111144123401001341
642213251500445355
72420012316402314
oct264363320470607
947818157046408
1012402175406471
113a51807769294
12148375b54985b
136bc69b92b396
1430c3a8a59d0b
151679207c8e4b
hexb479b427187

12402175406471 has 2 divisors, whose sum is σ = 12402175406472. Its totient is φ = 12402175406470.

The previous prime is 12402175406443. The next prime is 12402175406573. The reversal of 12402175406471 is 17460457120421.

12402175406471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12402175406471 - 210 = 12402175405447 is a prime.

It is a super-3 number, since 3×124021754064713 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12402175406441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201087703235 + 6201087703236.

It is an arithmetic number, because the mean of its divisors is an integer number (6201087703236).

Almost surely, 212402175406471 is an apocalyptic number.

12402175406471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12402175406471 is an equidigital number, since it uses as much as digits as its factorization.

12402175406471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 376320, while the sum is 44.

The spelling of 12402175406471 in words is "twelve trillion, four hundred two billion, one hundred seventy-five million, four hundred six thousand, four hundred seventy-one".