1240332244889 has 2 divisors, whose sum is σ = 1240332244890. Its totient is φ = 1240332244888.

The previous prime is 1240332244847. The next prime is 1240332244891. The reversal of 1240332244889 is 9884422330421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1227903339664 + 12428905225 = 1108108^2 + 111485^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1240332244889 is a prime.

It is a super-2 number, since 2×1240332244889² (a number of 25 digits) contains 22 as substring.

Together with 1240332244891, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1240332244819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620166122444 + 620166122445.

It is an arithmetic number, because the mean of its divisors is an integer number (620166122445).

Almost surely, 2^{1240332244889} is an apocalyptic number.

It is an amenable number.

1240332244889 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240332244889 is an equidigital number, since it uses as much as digits as its factorization.

1240332244889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2654208, while the sum is 50.

The spelling of 1240332244889 in words is "one trillion, two hundred forty billion, three hundred thirty-two million, two hundred forty-four thousand, eight hundred eighty-nine".