Base | Representation |
---|---|
bin | 111001110000100000… |
… | …1000101011100011111 |
3 | 102212011011022100121020 |
4 | 1303201001011130133 |
5 | 4013010231223320 |
6 | 132551444135223 |
7 | 11650453443603 |
oct | 1634101053437 |
9 | 385134270536 |
10 | 124034242335 |
11 | 4866a1070a3 |
12 | 20056997513 |
13 | b908c37a03 |
14 | 6009051503 |
15 | 335e241940 |
hex | 1ce104571f |
124034242335 has 64 divisors (see below), whose sum is σ = 212525254656. Its totient is φ = 61632806400.
The previous prime is 124034242253. The next prime is 124034242337. The reversal of 124034242335 is 533242430421.
It is not a de Polignac number, because 124034242335 - 27 = 124034242207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 124034242296 and 124034242305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (124034242337) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2139025 + ... + 2196245.
It is an arithmetic number, because the mean of its divisors is an integer number (3320707104).
Almost surely, 2124034242335 is an apocalyptic number.
124034242335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
124034242335 is a deficient number, since it is larger than the sum of its proper divisors (88491012321).
124034242335 is a wasteful number, since it uses less digits than its factorization.
124034242335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57416.
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 124034242335 its reverse (533242430421), we get a palindrome (657276672756).
The spelling of 124034242335 in words is "one hundred twenty-four billion, thirty-four million, two hundred forty-two thousand, three hundred thirty-five".
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