12404041121 has 2 divisors, whose sum is σ = 12404041122. Its totient is φ = 12404041120.

The previous prime is 12404041103. The next prime is 12404041123. The reversal of 12404041121 is 12114040421.

12404041121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12383238400 + 20802721 = 111280^2 + 4561^2 .

It is a cyclic number.

It is not a de Polignac number, because 12404041121 - 2⁶ = 12404041057 is a prime.

It is a super-2 number, since 2×12404041121² (a number of 21 digits) contains 22 as substring.

Together with 12404041123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12404041093 and 12404041102.

It is not a weakly prime, because it can be changed into another prime (12404041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202020560 + 6202020561.

It is an arithmetic number, because the mean of its divisors is an integer number (6202020561).

Almost surely, 2^12404041121 is an apocalyptic number.

It is an amenable number.

12404041121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12404041121 is an equidigital number, since it uses as much as digits as its factorization.

12404041121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 12404041121 its reverse (12114040421), we get a palindrome (24518081542).

The spelling of 12404041121 in words is "twelve billion, four hundred four million, forty-one thousand, one hundred twenty-one".