Base | Representation |
---|---|
bin | 1011010010000000101010… |
… | …0001101001010110011010 |
3 | 1121220211000000122121202002 |
4 | 2310200022201221112122 |
5 | 3111211434242040010 |
6 | 42214201023241002 |
7 | 2420106504402251 |
oct | 264401241512632 |
9 | 47824000577662 |
10 | 12404042143130 |
11 | 3a52585465160 |
12 | 1483ba0749162 |
13 | 6bc9085b67a1 |
14 | 30c504945798 |
15 | 1679ce6161a5 |
hex | b480a86959a |
12404042143130 has 64 divisors (see below), whose sum is σ = 24570371177856. Its totient is φ = 4471219200000.
The previous prime is 12404042143109. The next prime is 12404042143211. The reversal of 12404042143130 is 3134124040421.
It is a super-2 number, since 2×124040421431302 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12404042143093 and 12404042143102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4926005 + ... + 7005255.
It is an arithmetic number, because the mean of its divisors is an integer number (383912049654).
Almost surely, 212404042143130 is an apocalyptic number.
12404042143130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12404042143130 is a deficient number, since it is larger than the sum of its proper divisors (12166329034726).
12404042143130 is a wasteful number, since it uses less digits than its factorization.
12404042143130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2079743.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 12404042143130 its reverse (3134124040421), we get a palindrome (15538166183551).
The spelling of 12404042143130 in words is "twelve trillion, four hundred four billion, forty-two million, one hundred forty-three thousand, one hundred thirty".
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