Base | Representation |
---|---|
bin | 11100001101000001101001… |
… | …111101000110011000111000 |
3 | 121021012011001001112201022012 |
4 | 130031001221331012120320 |
5 | 112224234301340224422 |
6 | 1115451215513145052 |
7 | 35061424365150656 |
oct | 3415015175063070 |
9 | 537164031481265 |
10 | 124040433133112 |
11 | 3658328585a171 |
12 | 11ab3a4a0bb188 |
13 | 5429c68c4a332 |
14 | 228b8362c7dd6 |
15 | e5189a1534e2 |
hex | 70d069f46638 |
124040433133112 has 32 divisors (see below), whose sum is σ = 233997140686320. Its totient is φ = 61641844078080.
The previous prime is 124040433133093. The next prime is 124040433133139. The reversal of 124040433133112 is 211331334040421.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38997953 + ... + 42058544.
Almost surely, 2124040433133112 is an apocalyptic number.
It is an amenable number.
124040433133112 is a deficient number, since it is larger than the sum of its proper divisors (109956707553208).
124040433133112 is a wasteful number, since it uses less digits than its factorization.
124040433133112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81057671 (or 81057667 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 124040433133112 its reverse (211331334040421), we get a palindrome (335371767173533).
The spelling of 124040433133112 in words is "one hundred twenty-four trillion, forty billion, four hundred thirty-three million, one hundred thirty-three thousand, one hundred twelve".
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