Base | Representation |
---|---|
bin | 111001110000101101… |
… | …1010111010100110101 |
3 | 102212011122021100111201 |
4 | 1303201123113110311 |
5 | 4013014012200232 |
6 | 132552251532501 |
7 | 11650566135235 |
oct | 1634133272465 |
9 | 385148240451 |
10 | 124041131317 |
11 | 48672a91974 |
12 | 2005915a131 |
13 | b90a4aa52c |
14 | 6009d25cc5 |
15 | 335eb52be7 |
hex | 1ce16d7535 |
124041131317 has 2 divisors, whose sum is σ = 124041131318. Its totient is φ = 124041131316.
The previous prime is 124041131299. The next prime is 124041131321. The reversal of 124041131317 is 713131140421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92400192676 + 31640938641 = 303974^2 + 177879^2 .
It is a cyclic number.
It is not a de Polignac number, because 124041131317 - 211 = 124041129269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124041131117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62020565658 + 62020565659.
It is an arithmetic number, because the mean of its divisors is an integer number (62020565659).
Almost surely, 2124041131317 is an apocalyptic number.
It is an amenable number.
124041131317 is a deficient number, since it is larger than the sum of its proper divisors (1).
124041131317 is an equidigital number, since it uses as much as digits as its factorization.
124041131317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 124041131317 its reverse (713131140421), we get a palindrome (837172271738).
The spelling of 124041131317 in words is "one hundred twenty-four billion, forty-one million, one hundred thirty-one thousand, three hundred seventeen".
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