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124043115253 is a prime number
BaseRepresentation
bin111001110000110001…
…0111011101011110101
3102212011210000010221211
41303201202323223311
54013020014142003
6132552402241421
711650622040301
oct1634142735365
9385153003854
10124043115253
1148674117492
1220059956271
13b90aa23565
14600a2c0d01
15335ede596d
hex1ce18bbaf5

124043115253 has 2 divisors, whose sum is σ = 124043115254. Its totient is φ = 124043115252.

The previous prime is 124043115149. The next prime is 124043115277. The reversal of 124043115253 is 352511340421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72050906929 + 51992208324 = 268423^2 + 228018^2 .

It is a cyclic number.

It is not a de Polignac number, because 124043115253 - 213 = 124043107061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124043110253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62021557626 + 62021557627.

It is an arithmetic number, because the mean of its divisors is an integer number (62021557627).

Almost surely, 2124043115253 is an apocalyptic number.

It is an amenable number.

124043115253 is a deficient number, since it is larger than the sum of its proper divisors (1).

124043115253 is an equidigital number, since it uses as much as digits as its factorization.

124043115253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 124043115253 its reverse (352511340421), we get a palindrome (476554455674).

The spelling of 124043115253 in words is "one hundred twenty-four billion, forty-three million, one hundred fifteen thousand, two hundred fifty-three".