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124043414513 is a prime number
BaseRepresentation
bin111001110000110010…
…0000100101111110001
3102212011210120100110112
41303201210010233301
54013020103231023
6132552412511105
711650624424624
oct1634144045761
9385153510415
10124043414513
1148674301307
1220059a7b495
13b90aac9835
14600a35bdbb
15335ee54478
hex1ce1904bf1

124043414513 has 2 divisors, whose sum is σ = 124043414514. Its totient is φ = 124043414512.

The previous prime is 124043414507. The next prime is 124043414533. The reversal of 124043414513 is 315414340421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95262970609 + 28780443904 = 308647^2 + 169648^2 .

It is a cyclic number.

It is not a de Polignac number, because 124043414513 - 224 = 124026637297 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 124043414513.

It is not a weakly prime, because it can be changed into another prime (124043414533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62021707256 + 62021707257.

It is an arithmetic number, because the mean of its divisors is an integer number (62021707257).

Almost surely, 2124043414513 is an apocalyptic number.

It is an amenable number.

124043414513 is a deficient number, since it is larger than the sum of its proper divisors (1).

124043414513 is an equidigital number, since it uses as much as digits as its factorization.

124043414513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 124043414513 its reverse (315414340421), we get a palindrome (439457754934).

The spelling of 124043414513 in words is "one hundred twenty-four billion, forty-three million, four hundred fourteen thousand, five hundred thirteen".