Base | Representation |
---|---|
bin | 10111000110101111… |
… | …10111110111111001 |
3 | 1012000111111000201202 |
4 | 23203113313313321 |
5 | 200401040331133 |
6 | 5410522023545 |
7 | 616253352125 |
oct | 134327676771 |
9 | 35014430652 |
10 | 12404620793 |
11 | 52960a3224 |
12 | 24a2347bb5 |
13 | 1228c33406 |
14 | 859666585 |
15 | 4c90482e8 |
hex | 2e35f7df9 |
12404620793 has 2 divisors, whose sum is σ = 12404620794. Its totient is φ = 12404620792.
The previous prime is 12404620769. The next prime is 12404620819. The reversal of 12404620793 is 39702640421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12199644304 + 204976489 = 110452^2 + 14317^2 .
It is a cyclic number.
It is not a de Polignac number, because 12404620793 - 218 = 12404358649 is a prime.
It is a super-3 number, since 3×124046207933 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12404620993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202310396 + 6202310397.
It is an arithmetic number, because the mean of its divisors is an integer number (6202310397).
Almost surely, 212404620793 is an apocalyptic number.
It is an amenable number.
12404620793 is a deficient number, since it is larger than the sum of its proper divisors (1).
12404620793 is an equidigital number, since it uses as much as digits as its factorization.
12404620793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 38.
The spelling of 12404620793 in words is "twelve billion, four hundred four million, six hundred twenty thousand, seven hundred ninety-three".
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