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1240593889853 is a prime number
BaseRepresentation
bin10010000011011001001…
…010000111101000111101
311101121012010021101012102
4102003121022013220331
5130311214013433403
62345530532314445
7155426034034103
oct22033112075075
94347163241172
101240593889853
114391509aa39a
12180528472a25
138ccab706986
144408b92bc73
152240d8d4b88
hex120d9287a3d

1240593889853 has 2 divisors, whose sum is σ = 1240593889854. Its totient is φ = 1240593889852.

The previous prime is 1240593889813. The next prime is 1240593889891. The reversal of 1240593889853 is 3589883950421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 661492675684 + 579101214169 = 813322^2 + 760987^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240593889853 - 26 = 1240593889789 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1240593889853.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240593889813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620296944926 + 620296944927.

It is an arithmetic number, because the mean of its divisors is an integer number (620296944927).

Almost surely, 21240593889853 is an apocalyptic number.

It is an amenable number.

1240593889853 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240593889853 is an equidigital number, since it uses as much as digits as its factorization.

1240593889853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 74649600, while the sum is 65.

The spelling of 1240593889853 in words is "one trillion, two hundred forty billion, five hundred ninety-three million, eight hundred eighty-nine thousand, eight hundred fifty-three".