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1240678133 is a prime number
BaseRepresentation
bin100100111110011…
…0011111011110101
310012110112222102222
41021330303323311
510020103200013
6323040012125
742513406262
oct11174637365
93173488388
101240678133
1158736a932
122a7601045
1316a067896
14baabc269
1573dc3508
hex49f33ef5

1240678133 has 2 divisors, whose sum is σ = 1240678134. Its totient is φ = 1240678132.

The previous prime is 1240678123. The next prime is 1240678247. The reversal of 1240678133 is 3318760421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 928908484 + 311769649 = 30478^2 + 17657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1240678133 is a prime.

It is a super-3 number, since 3×12406781333 (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1240678093 and 1240678102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240678123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620339066 + 620339067.

It is an arithmetic number, because the mean of its divisors is an integer number (620339067).

Almost surely, 21240678133 is an apocalyptic number.

It is an amenable number.

1240678133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240678133 is an equidigital number, since it uses as much as digits as its factorization.

1240678133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 35.

The square root of 1240678133 is about 35223.2612487827. The cubic root of 1240678133 is about 1074.5328803041.

The spelling of 1240678133 in words is "one billion, two hundred forty million, six hundred seventy-eight thousand, one hundred thirty-three".