Base | Representation |
---|---|
bin | 111001110010110101… |
… | …1100101110111111001 |
3 | 102212100121112221210202 |
4 | 1303211223211313321 |
5 | 4013140244302243 |
6 | 133003321251545 |
7 | 11652423536021 |
oct | 1634553456771 |
9 | 385317487722 |
10 | 124112494073 |
11 | 486aa2a3857 |
12 | 20079033bb5 |
13 | b91c205409 |
14 | 60155c0a81 |
15 | 336604c4b8 |
hex | 1ce5ae5df9 |
124112494073 has 2 divisors, whose sum is σ = 124112494074. Its totient is φ = 124112494072.
The previous prime is 124112494069. The next prime is 124112494081. The reversal of 124112494073 is 370494211421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63995338729 + 60117155344 = 252973^2 + 245188^2 .
It is a cyclic number.
It is not a de Polignac number, because 124112494073 - 22 = 124112494069 is a prime.
It is a super-2 number, since 2×1241124940732 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (124112494003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62056247036 + 62056247037.
It is an arithmetic number, because the mean of its divisors is an integer number (62056247037).
Almost surely, 2124112494073 is an apocalyptic number.
It is an amenable number.
124112494073 is a deficient number, since it is larger than the sum of its proper divisors (1).
124112494073 is an equidigital number, since it uses as much as digits as its factorization.
124112494073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 38.
The spelling of 124112494073 in words is "one hundred twenty-four billion, one hundred twelve million, four hundred ninety-four thousand, seventy-three".
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