Base | Representation |
---|---|
bin | 11100001110001110100100… |
… | …001010000110110110010111 |
3 | 121021111001012021000102010112 |
4 | 130032032210022012312113 |
5 | 112232112413041000043 |
6 | 1115553154143513235 |
7 | 35100406666014623 |
oct | 3416164412066627 |
9 | 537431167012115 |
10 | 124123014000023 |
11 | 36605302582805 |
12 | 11b07a562b881b |
13 | 543499998641c |
14 | 229182bb24183 |
15 | e53aceec3518 |
hex | 70e3a4286d97 |
124123014000023 has 2 divisors, whose sum is σ = 124123014000024. Its totient is φ = 124123014000022.
The previous prime is 124123014000001. The next prime is 124123014000031. The reversal of 124123014000023 is 320000410321421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124123014000023 - 238 = 123848136093079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124123014000523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62061507000011 + 62061507000012.
It is an arithmetic number, because the mean of its divisors is an integer number (62061507000012).
Almost surely, 2124123014000023 is an apocalyptic number.
124123014000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
124123014000023 is an equidigital number, since it uses as much as digits as its factorization.
124123014000023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 124123014000023 its reverse (320000410321421), we get a palindrome (444123424321444).
The spelling of 124123014000023 in words is "one hundred twenty-four trillion, one hundred twenty-three billion, fourteen million, twenty-three", and thus it is an aban number.
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