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12412433141021 is a prime number
BaseRepresentation
bin1011010010011111111010…
…1010110000110100011101
31121221121122210210110220202
42310213332222300310131
53111331130341003041
642222105411353245
72420524443612044
oct264477652606435
947847583713822
1012412433141021
113a560a0a0a061
1214857428b2825
136c0644b388b4
1430ca9d10d55b
15167d210e7a9b
hexb49feab0d1d

12412433141021 has 2 divisors, whose sum is σ = 12412433141022. Its totient is φ = 12412433141020.

The previous prime is 12412433140973. The next prime is 12412433141041. The reversal of 12412433141021 is 12014133421421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12338604643225 + 73828497796 = 3512635^2 + 271714^2 .

It is a cyclic number.

It is not a de Polignac number, because 12412433141021 - 26 = 12412433140957 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12412433141041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6206216570510 + 6206216570511.

It is an arithmetic number, because the mean of its divisors is an integer number (6206216570511).

Almost surely, 212412433141021 is an apocalyptic number.

It is an amenable number.

12412433141021 is a deficient number, since it is larger than the sum of its proper divisors (1).

12412433141021 is an equidigital number, since it uses as much as digits as its factorization.

12412433141021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 12412433141021 its reverse (12014133421421), we get a palindrome (24426566562442).

The spelling of 12412433141021 in words is "twelve trillion, four hundred twelve billion, four hundred thirty-three million, one hundred forty-one thousand, twenty-one".