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12413034203413 is a prime number
BaseRepresentation
bin1011010010100010001001…
…1111101000100100010101
31121221200012200210121111211
42310220202133220210111
53111333343224002123
642222245202301421
72420545362554404
oct264504237504425
947850180717454
1012413034203413
113a5637a223138
121485890057871
136c070c516c0c
1430cb18c9163b
15167d58c7540d
hexb4a227e8915

12413034203413 has 2 divisors, whose sum is σ = 12413034203414. Its totient is φ = 12413034203412.

The previous prime is 12413034203389. The next prime is 12413034203441. The reversal of 12413034203413 is 31430243031421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11346610351729 + 1066423851684 = 3368473^2 + 1032678^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12413034203413 is a prime.

It is a super-2 number, since 2×124130342034132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12413034209413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6206517101706 + 6206517101707.

It is an arithmetic number, because the mean of its divisors is an integer number (6206517101707).

Almost surely, 212413034203413 is an apocalyptic number.

It is an amenable number.

12413034203413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12413034203413 is an equidigital number, since it uses as much as digits as its factorization.

12413034203413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 12413034203413 its reverse (31430243031421), we get a palindrome (43843277234834).

The spelling of 12413034203413 in words is "twelve trillion, four hundred thirteen billion, thirty-four million, two hundred three thousand, four hundred thirteen".