Base | Representation |
---|---|
bin | 11100001110010111111101… |
… | …101000010011100111001111 |
3 | 121021112000020112001111220112 |
4 | 130032113331220103213033 |
5 | 112232244044341222224 |
6 | 1120001543341310235 |
7 | 35101215030214151 |
oct | 3416277550234717 |
9 | 537460215044815 |
10 | 124133105023439 |
11 | 36609610707a86 |
12 | 11b099b186537b |
13 | 54359174935b5 |
14 | 2292107dbcad1 |
15 | e53ec0d6130e |
hex | 70e5fda139cf |
124133105023439 has 2 divisors, whose sum is σ = 124133105023440. Its totient is φ = 124133105023438.
The previous prime is 124133105023331. The next prime is 124133105023517. The reversal of 124133105023439 is 934320501331421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124133105023439 - 216 = 124133104957903 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 124133105023396 and 124133105023405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124133105023639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62066552511719 + 62066552511720.
It is an arithmetic number, because the mean of its divisors is an integer number (62066552511720).
Almost surely, 2124133105023439 is an apocalyptic number.
124133105023439 is a deficient number, since it is larger than the sum of its proper divisors (1).
124133105023439 is an equidigital number, since it uses as much as digits as its factorization.
124133105023439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 124133105023439 in words is "one hundred twenty-four trillion, one hundred thirty-three billion, one hundred five million, twenty-three thousand, four hundred thirty-nine".
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