Base | Representation |
---|---|
bin | 10111000111110011… |
… | …00001111111010111 |
3 | 1012001010002021222020 |
4 | 23203321201333113 |
5 | 200410320202210 |
6 | 5411435104223 |
7 | 616421350665 |
oct | 134371417727 |
9 | 35033067866 |
10 | 12413444055 |
11 | 52a007a281 |
12 | 24a52a2073 |
13 | 122aa0248c |
14 | 85a8c1c35 |
15 | 4c9bdc770 |
hex | 2e3e61fd7 |
12413444055 has 32 divisors (see below), whose sum is σ = 20555458560. Its totient is φ = 6389389440.
The previous prime is 12413444039. The next prime is 12413444077. The reversal of 12413444055 is 55044431421.
It is a happy number.
It is not a de Polignac number, because 12413444055 - 24 = 12413444039 is a prime.
It is a super-3 number, since 3×124134440553 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1284090 + ... + 1293720.
It is an arithmetic number, because the mean of its divisors is an integer number (642358080).
Almost surely, 212413444055 is an apocalyptic number.
12413444055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12413444055 is a deficient number, since it is larger than the sum of its proper divisors (8142014505).
12413444055 is a wasteful number, since it uses less digits than its factorization.
12413444055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12631.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 12413444055 its reverse (55044431421), we get a palindrome (67457875476).
The spelling of 12413444055 in words is "twelve billion, four hundred thirteen million, four hundred forty-four thousand, fifty-five".
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