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12413447252497 is a prime number
BaseRepresentation
bin1011010010100011101100…
…0111010010101000010001
31121221201021111000200100001
42310220323013102220101
53111340214444034442
642222354155330001
72420561536455214
oct264507307225021
947851244020301
1012413447252497
113a565713a1015
121485986450901
136c0776c76b65
1430cb57a9177b
15167d801652b7
hexb4a3b1d2a11

12413447252497 has 2 divisors, whose sum is σ = 12413447252498. Its totient is φ = 12413447252496.

The previous prime is 12413447252473. The next prime is 12413447252533. The reversal of 12413447252497 is 79425274431421.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10450937649681 + 1962509602816 = 3232791^2 + 1400896^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12413447252497 is a prime.

It is not a weakly prime, because it can be changed into another prime (12413447258497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6206723626248 + 6206723626249.

It is an arithmetic number, because the mean of its divisors is an integer number (6206723626249).

Almost surely, 212413447252497 is an apocalyptic number.

It is an amenable number.

12413447252497 is a deficient number, since it is larger than the sum of its proper divisors (1).

12413447252497 is an equidigital number, since it uses as much as digits as its factorization.

12413447252497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13547520, while the sum is 55.

The spelling of 12413447252497 in words is "twelve trillion, four hundred thirteen billion, four hundred forty-seven million, two hundred fifty-two thousand, four hundred ninety-seven".