Base | Representation |
---|---|
bin | 10010000100001001111… |
… | …001000110101100101011 |
3 | 11101200022002202221111001 |
4 | 102010021321012230223 |
5 | 130314402321410011 |
6 | 2350144021015431 |
7 | 155455222520326 |
oct | 22041171065453 |
9 | 4350262687431 |
10 | 1241411513131 |
11 | 439530487909 |
12 | 180716254577 |
13 | 900abc1a22a |
14 | 441283637bd |
15 | 2245a58d7c1 |
hex | 12109e46b2b |
1241411513131 has 2 divisors, whose sum is σ = 1241411513132. Its totient is φ = 1241411513130.
The previous prime is 1241411513107. The next prime is 1241411513137. The reversal of 1241411513131 is 1313151141421.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1241411513131 - 213 = 1241411504939 is a prime.
It is a super-2 number, since 2×12414115131312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1241411513131.
It is not a weakly prime, because it can be changed into another prime (1241411513137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620705756565 + 620705756566.
It is an arithmetic number, because the mean of its divisors is an integer number (620705756566).
Almost surely, 21241411513131 is an apocalyptic number.
1241411513131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241411513131 is an equidigital number, since it uses as much as digits as its factorization.
1241411513131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 28.
Adding to 1241411513131 its reverse (1313151141421), we get a palindrome (2554562654552).
The spelling of 1241411513131 in words is "one trillion, two hundred forty-one billion, four hundred eleven million, five hundred thirteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •