Base | Representation |
---|---|
bin | 1011010010100110010100… |
… | …0101100011101011111111 |
3 | 1121221210002120002011120022 |
4 | 2310221211011203223333 |
5 | 3111343140232104101 |
6 | 42222552112442355 |
7 | 2420615150123315 |
oct | 264514505435377 |
9 | 47853076064508 |
10 | 12414151441151 |
11 | 3a568a2941409 |
12 | 1485b422493bb |
13 | 6c0859b21935 |
14 | 30cbc33da0b5 |
15 | 167dc1db3a1b |
hex | b4a65163aff |
12414151441151 has 2 divisors, whose sum is σ = 12414151441152. Its totient is φ = 12414151441150.
The previous prime is 12414151441091. The next prime is 12414151441243. The reversal of 12414151441151 is 15114415141421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12414151441151 - 218 = 12414151179007 is a prime.
It is a super-2 number, since 2×124141514411512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12414151443151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6207075720575 + 6207075720576.
It is an arithmetic number, because the mean of its divisors is an integer number (6207075720576).
Almost surely, 212414151441151 is an apocalyptic number.
12414151441151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12414151441151 is an equidigital number, since it uses as much as digits as its factorization.
12414151441151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12800, while the sum is 35.
Adding to 12414151441151 its reverse (15114415141421), we get a palindrome (27528566582572).
The spelling of 12414151441151 in words is "twelve trillion, four hundred fourteen billion, one hundred fifty-one million, four hundred forty-one thousand, one hundred fifty-one".
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