Base | Representation |
---|---|
bin | 10010000100001010100… |
… | …010110110001011111111 |
3 | 11101200022212100212122212 |
4 | 102010022202312023333 |
5 | 130314413122034201 |
6 | 2350145051331035 |
7 | 155455414523405 |
oct | 22041242661377 |
9 | 4350285325585 |
10 | 1241422455551 |
11 | 439536681033 |
12 | 180719a50a7b |
13 | 900b127ba35 |
14 | 441299b1475 |
15 | 2245b500abb |
hex | 1210a8b62ff |
1241422455551 has 2 divisors, whose sum is σ = 1241422455552. Its totient is φ = 1241422455550.
The previous prime is 1241422455529. The next prime is 1241422455569. The reversal of 1241422455551 is 1555542241421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1241422455551 - 214 = 1241422439167 is a prime.
It is a super-2 number, since 2×12414224555512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1241422455499 and 1241422455508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1241422455751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620711227775 + 620711227776.
It is an arithmetic number, because the mean of its divisors is an integer number (620711227776).
Almost surely, 21241422455551 is an apocalyptic number.
1241422455551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241422455551 is an equidigital number, since it uses as much as digits as its factorization.
1241422455551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 320000, while the sum is 41.
Adding to 1241422455551 its reverse (1555542241421), we get a palindrome (2796964696972).
The spelling of 1241422455551 in words is "one trillion, two hundred forty-one billion, four hundred twenty-two million, four hundred fifty-five thousand, five hundred fifty-one".
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