Base | Representation |
---|---|
bin | 10010000100001100001… |
… | …100000101001011000111 |
3 | 11101200101210021102020020 |
4 | 102010030030011023013 |
5 | 130314442202321210 |
6 | 2350151514510223 |
7 | 155456201150466 |
oct | 22041414051307 |
9 | 4350353242206 |
10 | 1241450042055 |
11 | 4395502031a3 |
12 | 180727135373 |
13 | 900b6bba302 |
14 | 4412d5129dd |
15 | 2245db4e770 |
hex | 1210c3052c7 |
1241450042055 has 16 divisors (see below), whose sum is σ = 2072681809920. Its totient is φ = 633319441568.
The previous prime is 1241450041961. The next prime is 1241450042123. The reversal of 1241450042055 is 5502400541421.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1241450042055 - 214 = 1241450025671 is a prime.
It is a super-2 number, since 2×12414500420552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1799202615 + ... + 1799203304.
It is an arithmetic number, because the mean of its divisors is an integer number (129542613120).
Almost surely, 21241450042055 is an apocalyptic number.
1241450042055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1241450042055 is a deficient number, since it is larger than the sum of its proper divisors (831231767865).
1241450042055 is a wasteful number, since it uses less digits than its factorization.
1241450042055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3598405950.
The product of its (nonzero) digits is 32000, while the sum is 33.
Adding to 1241450042055 its reverse (5502400541421), we get a palindrome (6743850583476).
The spelling of 1241450042055 in words is "one trillion, two hundred forty-one billion, four hundred fifty million, forty-two thousand, fifty-five".
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