Base | Representation |
---|---|
bin | 10010000100001110111… |
… | …111001111011110001101 |
3 | 11101200112001122112102011 |
4 | 102010032333033132031 |
5 | 130320041213224023 |
6 | 2350200313301221 |
7 | 155460311310463 |
oct | 22041677173615 |
9 | 4350461575364 |
10 | 1241497008013 |
11 | 439574771439 |
12 | 18073aa04811 |
13 | 900c3852712 |
14 | 4413585a833 |
15 | 22462d2a50d |
hex | 1210efcf78d |
1241497008013 has 2 divisors, whose sum is σ = 1241497008014. Its totient is φ = 1241497008012.
The previous prime is 1241497007983. The next prime is 1241497008023. The reversal of 1241497008013 is 3108007941421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 939158686404 + 302338321609 = 969102^2 + 549853^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1241497008013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1241497008023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620748504006 + 620748504007.
It is an arithmetic number, because the mean of its divisors is an integer number (620748504007).
Almost surely, 21241497008013 is an apocalyptic number.
It is an amenable number.
1241497008013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241497008013 is an equidigital number, since it uses as much as digits as its factorization.
1241497008013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 40.
The spelling of 1241497008013 in words is "one trillion, two hundred forty-one billion, four hundred ninety-seven million, eight thousand, thirteen".
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