Base | Representation |
---|---|
bin | 1011010010110000100110… |
… | …1010010000011000010001 |
3 | 1121222001012222112202022022 |
4 | 2310230021222100120101 |
5 | 3111414314101243232 |
6 | 42224130104221225 |
7 | 2421043445006033 |
oct | 264541152203021 |
9 | 47861188482268 |
10 | 12416912524817 |
11 | 3a57a8a459439 |
12 | 1486592a6a815 |
13 | 6c0ba9b74658 |
14 | 30cda5dadc53 |
15 | 167ed44b2812 |
hex | b4b09a90611 |
12416912524817 has 2 divisors, whose sum is σ = 12416912524818. Its totient is φ = 12416912524816.
The previous prime is 12416912524787. The next prime is 12416912524823. The reversal of 12416912524817 is 71842521961421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10201789312576 + 2215123212241 = 3194024^2 + 1488329^2 .
It is a cyclic number.
It is not a de Polignac number, because 12416912524817 - 220 = 12416911476241 is a prime.
It is not a weakly prime, because it can be changed into another prime (12416912524847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6208456262408 + 6208456262409.
It is an arithmetic number, because the mean of its divisors is an integer number (6208456262409).
Almost surely, 212416912524817 is an apocalyptic number.
It is an amenable number.
12416912524817 is a deficient number, since it is larger than the sum of its proper divisors (1).
12416912524817 is an equidigital number, since it uses as much as digits as its factorization.
12416912524817 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1935360, while the sum is 53.
The spelling of 12416912524817 in words is "twelve trillion, four hundred sixteen billion, nine hundred twelve million, five hundred twenty-four thousand, eight hundred seventeen".
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