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12419832212113 is a prime number
BaseRepresentation
bin1011010010111011011110…
…1011111110101010010001
31121222022202110110020022211
42310232313223332222101
53111441304021241423
642225331523232121
72421206006643634
oct264566753765221
947868673406284
1012419832212113
113a59248554747
121487068818641
136c1253a19381
1430d1a1a6bc1b
1516810599010d
hexb4bb7afea91

12419832212113 has 2 divisors, whose sum is σ = 12419832212114. Its totient is φ = 12419832212112.

The previous prime is 12419832212111. The next prime is 12419832212131. The reversal of 12419832212113 is 31121223891421.

Together with next prime (12419832212131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9234992221569 + 3184839990544 = 3038913^2 + 1784612^2 .

It is a cyclic number.

It is not a de Polignac number, because 12419832212113 - 21 = 12419832212111 is a prime.

Together with 12419832212111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12419832212111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6209916106056 + 6209916106057.

It is an arithmetic number, because the mean of its divisors is an integer number (6209916106057).

Almost surely, 212419832212113 is an apocalyptic number.

It is an amenable number.

12419832212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12419832212113 is an equidigital number, since it uses as much as digits as its factorization.

12419832212113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 40.

The spelling of 12419832212113 in words is "twelve trillion, four hundred nineteen billion, eight hundred thirty-two million, two hundred twelve thousand, one hundred thirteen".