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12421455406141 is a prime number
BaseRepresentation
bin1011010011000001100001…
…1011111110010000111101
31121222110221120210000221011
42310300120123332100331
53112003120040444031
642230200550035221
72421264146605015
oct264603033762075
947873846700834
1012421455406141
113a59a00828411
121487440348b11
136c14520b3302
1430d2b747cc45
1516819d2216b1
hexb4c186fe43d

12421455406141 has 2 divisors, whose sum is σ = 12421455406142. Its totient is φ = 12421455406140.

The previous prime is 12421455406117. The next prime is 12421455406147. The reversal of 12421455406141 is 14160455412421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10182927744900 + 2238527661241 = 3191070^2 + 1496171^2 .

It is a cyclic number.

It is not a de Polignac number, because 12421455406141 - 27 = 12421455406013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12421455406094 and 12421455406103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12421455406147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210727703070 + 6210727703071.

It is an arithmetic number, because the mean of its divisors is an integer number (6210727703071).

Almost surely, 212421455406141 is an apocalyptic number.

It is an amenable number.

12421455406141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12421455406141 is an equidigital number, since it uses as much as digits as its factorization.

12421455406141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 153600, while the sum is 40.

The spelling of 12421455406141 in words is "twelve trillion, four hundred twenty-one billion, four hundred fifty-five million, four hundred six thousand, one hundred forty-one".