Base | Representation |
---|---|
bin | 1011010011000011101101… |
… | …0110111111110110010111 |
3 | 1121222112110102020202100022 |
4 | 2310300323112333312113 |
5 | 3112010320033220341 |
6 | 42230335035535355 |
7 | 2421314522632301 |
oct | 264607326776627 |
9 | 47875412222308 |
10 | 12422041304471 |
11 | 3a5a181524507 |
12 | 14875845ba55b |
13 | 6c15165b2406 |
14 | 30d3311d4971 |
15 | 1681d48a5e4b |
hex | b4c3b5bfd97 |
12422041304471 has 2 divisors, whose sum is σ = 12422041304472. Its totient is φ = 12422041304470.
The previous prime is 12422041304411. The next prime is 12422041304483. The reversal of 12422041304471 is 17440314022421.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12422041304471 is a prime.
It is a super-3 number, since 3×124220413044713 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12422041304411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6211020652235 + 6211020652236.
It is an arithmetic number, because the mean of its divisors is an integer number (6211020652236).
Almost surely, 212422041304471 is an apocalyptic number.
12422041304471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12422041304471 is an equidigital number, since it uses as much as digits as its factorization.
12422041304471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 12422041304471 its reverse (17440314022421), we get a palindrome (29862355326892).
The spelling of 12422041304471 in words is "twelve trillion, four hundred twenty-two billion, forty-one million, three hundred four thousand, four hundred seventy-one".
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