Base | Representation |
---|---|
bin | 1011010011001001101100… |
… | …0111001010010111000001 |
3 | 1121222200121101002110012201 |
4 | 2310302123013022113001 |
5 | 3112022112312002303 |
6 | 42231202303553201 |
7 | 2421402400423414 |
oct | 264623307122701 |
9 | 47880541073181 |
10 | 12423647765953 |
11 | 3a5a926309826 |
12 | 14879525bb801 |
13 | 6c171136b238 |
14 | 30d4446cbb7b |
15 | 16827a92e81d |
hex | b4c9b1ca5c1 |
12423647765953 has 2 divisors, whose sum is σ = 12423647765954. Its totient is φ = 12423647765952.
The previous prime is 12423647765897. The next prime is 12423647766041. The reversal of 12423647765953 is 35956774632421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9330752218384 + 3092895547569 = 3054628^2 + 1758663^2 .
It is a cyclic number.
It is not a de Polignac number, because 12423647765953 - 221 = 12423645668801 is a prime.
It is not a weakly prime, because it can be changed into another prime (12423647765153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6211823882976 + 6211823882977.
It is an arithmetic number, because the mean of its divisors is an integer number (6211823882977).
Almost surely, 212423647765953 is an apocalyptic number.
It is an amenable number.
12423647765953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12423647765953 is an equidigital number, since it uses as much as digits as its factorization.
12423647765953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 228614400, while the sum is 64.
The spelling of 12423647765953 in words is "twelve trillion, four hundred twenty-three billion, six hundred forty-seven million, seven hundred sixty-five thousand, nine hundred fifty-three".
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