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12424003513 is a prime number
BaseRepresentation
bin10111001001000011…
…10011111110111001
31012001211221202211021
423210201303332321
5200421021103023
65412453302441
7616610200405
oct134441637671
935054852737
1012424003513
1152a60317a9
1224a8934a21
13122cc5b88c
1485c070105
154caac635d
hex2e4873fb9

12424003513 has 2 divisors, whose sum is σ = 12424003514. Its totient is φ = 12424003512.

The previous prime is 12424003469. The next prime is 12424003531. The reversal of 12424003513 is 31530042421.

Together with next prime (12424003531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9912790969 + 2511212544 = 99563^2 + 50112^2 .

It is a cyclic number.

It is not a de Polignac number, because 12424003513 - 29 = 12424003001 is a prime.

It is a super-3 number, since 3×124240035133 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12424003313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6212001756 + 6212001757.

It is an arithmetic number, because the mean of its divisors is an integer number (6212001757).

Almost surely, 212424003513 is an apocalyptic number.

It is an amenable number.

12424003513 is a deficient number, since it is larger than the sum of its proper divisors (1).

12424003513 is an equidigital number, since it uses as much as digits as its factorization.

12424003513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 12424003513 its reverse (31530042421), we get a palindrome (43954045934).

The spelling of 12424003513 in words is "twelve billion, four hundred twenty-four million, three thousand, five hundred thirteen".