Base | Representation |
---|---|
bin | 10010000101000100110… |
… | …111110111010110101001 |
3 | 11101202212001202022111002 |
4 | 102011010313313112221 |
5 | 130323414131401011 |
6 | 2350430130044345 |
7 | 155521566425534 |
oct | 22050467672651 |
9 | 4352761668432 |
10 | 1242401043881 |
11 | 439998aaaa18 |
12 | 1809517196b5 |
13 | 90208c3009a |
14 | 441bd947a1b |
15 | 224b73a2c3b |
hex | 12144df75a9 |
1242401043881 has 2 divisors, whose sum is σ = 1242401043882. Its totient is φ = 1242401043880.
The previous prime is 1242401043853. The next prime is 1242401043889. The reversal of 1242401043881 is 1883401042421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1220271506281 + 22129537600 = 1104659^2 + 148760^2 .
It is a cyclic number.
It is not a de Polignac number, because 1242401043881 - 26 = 1242401043817 is a prime.
It is a super-2 number, since 2×12424010438812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1242401043889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621200521940 + 621200521941.
It is an arithmetic number, because the mean of its divisors is an integer number (621200521941).
Almost surely, 21242401043881 is an apocalyptic number.
It is an amenable number.
1242401043881 is a deficient number, since it is larger than the sum of its proper divisors (1).
1242401043881 is an equidigital number, since it uses as much as digits as its factorization.
1242401043881 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 49152, while the sum is 38.
The spelling of 1242401043881 in words is "one trillion, two hundred forty-two billion, four hundred one million, forty-three thousand, eight hundred eighty-one".
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