Base | Representation |
---|---|
bin | 10010000101001011100… |
… | …011000110001010000011 |
3 | 11101210010212111022021121 |
4 | 102011023203012022003 |
5 | 130324131314240003 |
6 | 2350445210333111 |
7 | 155524426403044 |
oct | 22051343061203 |
9 | 4353125438247 |
10 | 1242513040003 |
11 | 439a462452a4 |
12 | 18098312a197 |
13 | 902261b3b91 |
14 | 441d077c8cb |
15 | 224c2126cbd |
hex | 1214b8c6283 |
1242513040003 has 2 divisors, whose sum is σ = 1242513040004. Its totient is φ = 1242513040002.
The previous prime is 1242513039979. The next prime is 1242513040019. The reversal of 1242513040003 is 3000403152421.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1242513040003 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1242513040003.
It is not a weakly prime, because it can be changed into another prime (1242513040033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621256520001 + 621256520002.
It is an arithmetic number, because the mean of its divisors is an integer number (621256520002).
Almost surely, 21242513040003 is an apocalyptic number.
1242513040003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1242513040003 is an equidigital number, since it uses as much as digits as its factorization.
1242513040003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1242513040003 its reverse (3000403152421), we get a palindrome (4242916192424).
The spelling of 1242513040003 in words is "one trillion, two hundred forty-two billion, five hundred thirteen million, forty thousand, three".
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