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12430041410399 is a prime number
BaseRepresentation
bin1011010011100001100000…
…1100111110101101011111
31122000022002221212020112212
42310320120030332231133
53112123211100113044
642234140541551035
72422020004463264
oct264703014765537
948008087766485
1012430041410399
113a626073644a8
12148903787547b
136c21bcb617c2
1430d88d8c926b
15168501dc2a9e
hexb4e1833eb5f

12430041410399 has 2 divisors, whose sum is σ = 12430041410400. Its totient is φ = 12430041410398.

The previous prime is 12430041410389. The next prime is 12430041410419. The reversal of 12430041410399 is 99301414003421.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12430041410399 - 212 = 12430041406303 is a prime.

It is a super-2 number, since 2×124300414103992 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12430041410389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6215020705199 + 6215020705200.

It is an arithmetic number, because the mean of its divisors is an integer number (6215020705200).

Almost surely, 212430041410399 is an apocalyptic number.

12430041410399 is a deficient number, since it is larger than the sum of its proper divisors (1).

12430041410399 is an equidigital number, since it uses as much as digits as its factorization.

12430041410399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 12430041410399 in words is "twelve trillion, four hundred thirty billion, forty-one million, four hundred ten thousand, three hundred ninety-nine".