Base | Representation |
---|---|
bin | 1011010011100001100000… |
… | …1100111110101111000111 |
3 | 1122000022002221212020200201 |
4 | 2310320120030332233013 |
5 | 3112123211100114003 |
6 | 42234140541551331 |
7 | 2422020004463503 |
oct | 264703014765707 |
9 | 48008087766621 |
10 | 12430041410503 |
11 | 3a62607364592 |
12 | 1489037875547 |
13 | 6c21bcb61872 |
14 | 30d88d8c9303 |
15 | 168501dc2b1d |
hex | b4e1833ebc7 |
12430041410503 has 2 divisors, whose sum is σ = 12430041410504. Its totient is φ = 12430041410502.
The previous prime is 12430041410441. The next prime is 12430041410537. The reversal of 12430041410503 is 30501414003421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12430041410503 - 217 = 12430041279431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12430041410803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6215020705251 + 6215020705252.
It is an arithmetic number, because the mean of its divisors is an integer number (6215020705252).
Almost surely, 212430041410503 is an apocalyptic number.
12430041410503 is a deficient number, since it is larger than the sum of its proper divisors (1).
12430041410503 is an equidigital number, since it uses as much as digits as its factorization.
12430041410503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 12430041410503 its reverse (30501414003421), we get a palindrome (42931455413924).
The spelling of 12430041410503 in words is "twelve trillion, four hundred thirty billion, forty-one million, four hundred ten thousand, five hundred three".
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