Base | Representation |
---|---|
bin | 11100010000111100110101… |
… | …110111010001101110100111 |
3 | 121022010221012112121101222022 |
4 | 130100330311313101232213 |
5 | 112243144132341143421 |
6 | 1120215142501053355 |
7 | 35120053130622206 |
oct | 3420746567215647 |
9 | 538127175541868 |
10 | 124310142131111 |
11 | 366776a9524312 |
12 | 11b3817b0b725b |
13 | 544951c316801 |
14 | 229a9004b123d |
15 | e588d33a57ab |
hex | 710f35dd1ba7 |
124310142131111 has 2 divisors, whose sum is σ = 124310142131112. Its totient is φ = 124310142131110.
The previous prime is 124310142131081. The next prime is 124310142131129. The reversal of 124310142131111 is 111131241013421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124310142131111 - 214 = 124310142114727 is a prime.
It is a super-2 number, since 2×1243101421311112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124310142131191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62155071065555 + 62155071065556.
It is an arithmetic number, because the mean of its divisors is an integer number (62155071065556).
Almost surely, 2124310142131111 is an apocalyptic number.
124310142131111 is a deficient number, since it is larger than the sum of its proper divisors (1).
124310142131111 is an equidigital number, since it uses as much as digits as its factorization.
124310142131111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 26.
Adding to 124310142131111 its reverse (111131241013421), we get a palindrome (235441383144532).
The spelling of 124310142131111 in words is "one hundred twenty-four trillion, three hundred ten billion, one hundred forty-two million, one hundred thirty-one thousand, one hundred eleven".
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