Base | Representation |
---|---|
bin | 111001111000110010… |
… | …1001001011100000011 |
3 | 102212212112012120122021 |
4 | 1303301211021130003 |
5 | 4014042401200311 |
6 | 133035212222311 |
7 | 11660366452603 |
oct | 1636145113403 |
9 | 385775176567 |
10 | 124312131331 |
11 | 487a1a59223 |
12 | 20113a6a997 |
13 | b95169357b |
14 | 6033d0ac03 |
15 | 3378834171 |
hex | 1cf1949703 |
124312131331 has 2 divisors, whose sum is σ = 124312131332. Its totient is φ = 124312131330.
The previous prime is 124312131313. The next prime is 124312131347. The reversal of 124312131331 is 133131213421.
Together with previous prime (124312131313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124312131331 - 213 = 124312123139 is a prime.
It is a super-2 number, since 2×1243121313312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124312131296 and 124312131305.
It is not a weakly prime, because it can be changed into another prime (124312131301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62156065665 + 62156065666.
It is an arithmetic number, because the mean of its divisors is an integer number (62156065666).
Almost surely, 2124312131331 is an apocalyptic number.
124312131331 is a deficient number, since it is larger than the sum of its proper divisors (1).
124312131331 is an equidigital number, since it uses as much as digits as its factorization.
124312131331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296, while the sum is 25.
Adding to 124312131331 its reverse (133131213421), we get a palindrome (257443344752).
The spelling of 124312131331 in words is "one hundred twenty-four billion, three hundred twelve million, one hundred thirty-one thousand, three hundred thirty-one".
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