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124312554130 = 2535335216021
BaseRepresentation
bin111001111000110011…
…0110000101010010010
3102212212120000001121111
41303301212300222102
54014043003213010
6133035225243534
711660403163342
oct1636146605222
9385776001544
10124312554130
11487a2217946
12201140335aa
13b9517b0b4b
146033dbad22
1533788b958a
hex1cf19b0a92

124312554130 has 16 divisors (see below), whose sum is σ = 224396492184. Its totient is φ = 49584156160.

The previous prime is 124312554127. The next prime is 124312554161. The reversal of 124312554130 is 31455213421.

It can be written as a sum of positive squares in 4 ways, for example, as 97566895449 + 26745658681 = 312357^2 + 163541^2 .

It is a super-2 number, since 2×1243125541302 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 124312554092 and 124312554101.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17604481 + ... + 17611540.

Almost surely, 2124312554130 is an apocalyptic number.

124312554130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

124312554130 is a deficient number, since it is larger than the sum of its proper divisors (100083938054).

124312554130 is a wasteful number, since it uses less digits than its factorization.

124312554130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35216381.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 124312554130 its reverse (31455213421), we get a palindrome (155767767551).

The spelling of 124312554130 in words is "one hundred twenty-four billion, three hundred twelve million, five hundred fifty-four thousand, one hundred thirty".

Divisors: 1 2 5 10 353 706 1765 3530 35216021 70432042 176080105 352160210 12431255413 24862510826 62156277065 124312554130