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12431750413 is a prime number
BaseRepresentation
bin10111001001111110…
…10111010100001101
31012002101112100120111
423210333113110031
5200430012003123
65413331320021
7620033064205
oct134477272415
935071470514
1012431750413
1152aa4430a5
1224ab450011
131231741a44
1485d0c9405
154cb60690d
hex2e4fd750d

12431750413 has 2 divisors, whose sum is σ = 12431750414. Its totient is φ = 12431750412.

The previous prime is 12431750399. The next prime is 12431750477. The reversal of 12431750413 is 31405713421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9746230729 + 2685519684 = 98723^2 + 51822^2 .

It is a cyclic number.

It is not a de Polignac number, because 12431750413 - 29 = 12431749901 is a prime.

It is a super-2 number, since 2×124317504132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12431750813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6215875206 + 6215875207.

It is an arithmetic number, because the mean of its divisors is an integer number (6215875207).

Almost surely, 212431750413 is an apocalyptic number.

It is an amenable number.

12431750413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12431750413 is an equidigital number, since it uses as much as digits as its factorization.

12431750413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 12431750413 in words is "twelve billion, four hundred thirty-one million, seven hundred fifty thousand, four hundred thirteen".