Search a number
-
+
124331023 is a prime number
BaseRepresentation
bin1110110100100…
…10010000001111
322122221200002201
413122102100033
5223312043043
620200502331
73036540055
oct732222017
9278850081
10124331023
11641aa813
123577a9a7
131c9b236b
14127261d5
15adadc4d
hex769240f

124331023 has 2 divisors, whose sum is σ = 124331024. Its totient is φ = 124331022.

The previous prime is 124330981. The next prime is 124331059. The reversal of 124331023 is 320133421.

It is a strong prime.

It is an emirp because it is prime and its reverse (320133421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 124331023 - 213 = 124322831 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124331083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62165511 + 62165512.

It is an arithmetic number, because the mean of its divisors is an integer number (62165512).

Almost surely, 2124331023 is an apocalyptic number.

124331023 is a deficient number, since it is larger than the sum of its proper divisors (1).

124331023 is an equidigital number, since it uses as much as digits as its factorization.

124331023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 124331023 is about 11150.3821907592. The cubic root of 124331023 is about 499.1064347001.

Adding to 124331023 its reverse (320133421), we get a palindrome (444464444).

It can be divided in two parts, 12433 and 1023, that added together give a square (13456 = 1162).

The spelling of 124331023 in words is "one hundred twenty-four million, three hundred thirty-one thousand, twenty-three".