Base | Representation |
---|---|
bin | 111001111001010111… |
… | …0010100110000011111 |
3 | 102212220212022011121011 |
4 | 1303302232110300133 |
5 | 4014112304023312 |
6 | 133041135320051 |
7 | 11661021506422 |
oct | 1636256246037 |
9 | 385825264534 |
10 | 124331314207 |
11 | 48801870641 |
12 | 2011a380027 |
13 | b95564ba99 |
14 | 60366a19b9 |
15 | 337a372da7 |
hex | 1cf2b94c1f |
124331314207 has 2 divisors, whose sum is σ = 124331314208. Its totient is φ = 124331314206.
The previous prime is 124331314183. The next prime is 124331314229. The reversal of 124331314207 is 702413133421.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124331314207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124331314007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62165657103 + 62165657104.
It is an arithmetic number, because the mean of its divisors is an integer number (62165657104).
Almost surely, 2124331314207 is an apocalyptic number.
124331314207 is a deficient number, since it is larger than the sum of its proper divisors (1).
124331314207 is an equidigital number, since it uses as much as digits as its factorization.
124331314207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 124331314207 its reverse (702413133421), we get a palindrome (826744447628).
The spelling of 124331314207 in words is "one hundred twenty-four billion, three hundred thirty-one million, three hundred fourteen thousand, two hundred seven".
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