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12433264500 = 22353171513229
BaseRepresentation
bin10111001010001010…
…01000111101110100
31012002111101021111210
423211011020331310
5200430403431000
65413424001420
7620052001356
oct134505107564
935074337453
1012433264500
115300287708
1224aba60270
131231b51c57
1485d3a10d6
154cb805350
hex2e5148f74

12433264500 has 192 divisors, whose sum is σ = 38601239040. Its totient is φ = 3098880000.

The previous prime is 12433264499. The next prime is 12433264553. The reversal of 12433264500 is 546233421.

12433264500 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×124332645002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3848886 + ... + 3852114.

It is an arithmetic number, because the mean of its divisors is an integer number (201048120).

Almost surely, 212433264500 is an apocalyptic number.

12433264500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12433264500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19300619520).

12433264500 is an abundant number, since it is smaller than the sum of its proper divisors (26167974540).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12433264500 is a wasteful number, since it uses less digits than its factorization.

12433264500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3419 (or 3407 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 12433264500 its reverse (546233421), we get a palindrome (12979497921).

The spelling of 12433264500 in words is "twelve billion, four hundred thirty-three million, two hundred sixty-four thousand, five hundred".