12433340131 has 2 divisors, whose sum is σ = 12433340132. Its totient is φ = 12433340130.

The previous prime is 12433340113. The next prime is 12433340203. The reversal of 12433340131 is 13104333421.

Together with previous prime (12433340113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12433340131 - 2¹⁷ = 12433209059 is a prime.

It is a super-2 number, since 2×12433340131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12433340096 and 12433340105.

It is not a weakly prime, because it can be changed into another prime (12433340111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216670065 + 6216670066.

It is an arithmetic number, because the mean of its divisors is an integer number (6216670066).

Almost surely, 2^12433340131 is an apocalyptic number.

12433340131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12433340131 is an equidigital number, since it uses as much as digits as its factorization.

12433340131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12433340131 its reverse (13104333421), we get a palindrome (25537673552).

The spelling of 12433340131 in words is "twelve billion, four hundred thirty-three million, three hundred forty thousand, one hundred thirty-one".