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1243340200131 = 31827732267549
BaseRepresentation
bin10010000101111100110…
…110011101100011000011
311101212021111221101122220
4102011330312131203003
5130332330042401011
62351103235302123
7155554062216441
oct22057466354303
94355244841586
101243340200131
1143a330146a07
12180b7414a943
1390328686243
144426c577b91
152251ea66506
hex1217cd9d8c3

1243340200131 has 8 divisors (see below), whose sum is σ = 1657796734800. Its totient is φ = 828888566112.

The previous prime is 1243340200057. The next prime is 1243340200153. The reversal of 1243340200131 is 1310020433421.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-1243340200131 is a prime.

It is a super-2 number, since 2×12433402001312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1243340200181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 585456 + ... + 1682093.

It is an arithmetic number, because the mean of its divisors is an integer number (207224591850).

Almost surely, 21243340200131 is an apocalyptic number.

1243340200131 is a deficient number, since it is larger than the sum of its proper divisors (414456534669).

1243340200131 is a wasteful number, since it uses less digits than its factorization.

1243340200131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2450325.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 1243340200131 its reverse (1310020433421), we get a palindrome (2553360633552).

The spelling of 1243340200131 in words is "one trillion, two hundred forty-three billion, three hundred forty million, two hundred thousand, one hundred thirty-one".

Divisors: 1 3 182773 548319 2267549 6802647 414446733377 1243340200131