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1243340200153 is a prime number
BaseRepresentation
bin10010000101111100110…
…110011101100011011001
311101212021111221101200201
4102011330312131203121
5130332330042401103
62351103235302201
7155554062216502
oct22057466354331
94355244841621
101243340200153
1143a330146a27
12180b7414a961
139032868625c
144426c577ba9
152251ea6651d
hex1217cd9d8d9

1243340200153 has 2 divisors, whose sum is σ = 1243340200154. Its totient is φ = 1243340200152.

The previous prime is 1243340200057. The next prime is 1243340200163. The reversal of 1243340200153 is 3510020433421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 855277235344 + 388062964809 = 924812^2 + 622947^2 .

It is a cyclic number.

It is not a de Polignac number, because 1243340200153 - 221 = 1243338103001 is a prime.

It is not a weakly prime, because it can be changed into another prime (1243340200163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621670100076 + 621670100077.

It is an arithmetic number, because the mean of its divisors is an integer number (621670100077).

Almost surely, 21243340200153 is an apocalyptic number.

It is an amenable number.

1243340200153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243340200153 is an equidigital number, since it uses as much as digits as its factorization.

1243340200153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 1243340200153 its reverse (3510020433421), we get a palindrome (4753360633574).

The spelling of 1243340200153 in words is "one trillion, two hundred forty-three billion, three hundred forty million, two hundred thousand, one hundred fifty-three".