Base | Representation |
---|---|
bin | 1011010011110001110011… |
… | …0110010110010110111011 |
3 | 1122000201101201021122100002 |
4 | 2310330130312112112323 |
5 | 3112211140032100243 |
6 | 42240142512503215 |
7 | 2422233243630005 |
oct | 264743466262673 |
9 | 48021351248302 |
10 | 12434414331323 |
11 | 3a644507a8736 |
12 | 1489a5824ab0b |
13 | 6c2738b0318a |
14 | 30db86595375 |
15 | 1686aac5ceb8 |
hex | b4f1cd965bb |
12434414331323 has 2 divisors, whose sum is σ = 12434414331324. Its totient is φ = 12434414331322.
The previous prime is 12434414331319. The next prime is 12434414331349. The reversal of 12434414331323 is 32313341443421.
It is a weak prime.
It is an emirp because it is prime and its reverse (32313341443421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12434414331323 - 22 = 12434414331319 is a prime.
It is a super-2 number, since 2×124344143313232 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12434414351323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6217207165661 + 6217207165662.
It is an arithmetic number, because the mean of its divisors is an integer number (6217207165662).
Almost surely, 212434414331323 is an apocalyptic number.
12434414331323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12434414331323 is an equidigital number, since it uses as much as digits as its factorization.
12434414331323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 248832, while the sum is 38.
Adding to 12434414331323 its reverse (32313341443421), we get a palindrome (44747755774744).
The spelling of 12434414331323 in words is "twelve trillion, four hundred thirty-four billion, four hundred fourteen million, three hundred thirty-one thousand, three hundred twenty-three".
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